Question

The integral enthalpy of solution in kJ of one mole of $H_{2}S{O}_4$ dissolved in $n$ mole of water is given by:

$\Delta H_s=\frac{75.6\times n}{n+1.8}$

Calculate $\Delta H$ for $H_{2}S{O}_4$ dissolved in 2 mole of $H_{2}O$.

• A. - 48.54 kJ
• B. 39.79 kJ
• C. 48.54 kJ
• D. 75.60 kJ

Answer 1

Answer: (B)

39.79 kJ

According to given,

The integral enthalpy of solution in kJ of one mole of $H_{2}S{O}_4$ dissolved in $n$ mole of water is given by:

$\Delta H_s=\frac{75.6\times n}{n+1.8}$

So, for
1 mole of $H_{2}S{O}_4$ dissolved in 2 moles of $H_{2}O$

$\Delta H=\frac{75.6\times 2}{1+1.8}=39.79kJ$