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Question

The integral 2x12+5x9(x5+x3+1)3dx is equal to

A
x102(x5+x3+1)2+C
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B
x52(x5+x3+1)2+C
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C
x102(x5+x3+1)2+C
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D
x52(x5+x3+1)2+C
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Solution

The correct option is A x102(x5+x3+1)2+C
2x12+5x9(x5+x3+1)3dx
2x12+5x9x15(1+x2+x5)3dx

2x3+5x6(1+x2+x5)3dx
1+x2+x5=t

2x35x6dx=dt
dtt3t3+13+1+c

12t2+c12(1+x2+x5)2+c

x102(1+x3+x5)2+c

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