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Question

The integral 2x12+5x9(x5+x3+1)3dx is equal to:

A
x5(x5+x3+1)2+C
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B
x102(x5+x3+1)2+C
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C
x52(x5+x3+1)2+C
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D
x102(x5+x3+1)2+C
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Solution

The correct option is B x102(x5+x3+1)2+C
2x12+5x9(x5+x3+1)3dx
=2x12+5x9x15(x5+x2+1)3dx
=2x3+5x6(x5+x2+1)3dx

Let x5+x2+1=t

dtt3=12t2+c

=x102(x5+x3+1)2+c

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