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Question

The integral of x2xx3x2+x1 w.r.t x is

A
12log|x2+1|+C
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B
12log|x21|+C
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C
log|x2+1|+C
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D
log|x21|+C
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Solution

The correct option is A 12log|x2+1|+C
x2xx3x2+x1dxx(x1)x2(x1)+1(x1)dxx(x2+1)dxLetx2+1=t2xdx=dt12dtt=12logt+c=12log(x2+1)+cAns.

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