The integral of x2−xx3−x2+x−1 with respect to x is
(where C is constant of integration)
A
12ln|x2+1|+C
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B
12ln|x2−1|+C
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C
ln|x2+1|+C
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D
ln|x2−1|+C
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Solution
The correct option is A12ln|x2+1|+C Let I=∫x2−xx3−x2+x−1dx ⇒I=∫x(x−1)x2(x−1)+(x−1)dx ⇒I=∫xdxx2+1 ⇒I=12∫2xdx(x2+1)
Let x2+1=t ⇒2xdx=dt ∴I=12∫dtt ⇒I=12ln|t|+C ∴I=12ln∣∣x2+1∣∣+C