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Question

The integral of 1sinxcos2xdx is

(a) tanx+secx+c       (b) tanxsecx+c
(a) secxtanx+c       (b) tanxlnsecx+c


Solution

I=1sinxcos2xdx
  =1cos2xdxsinxcos2xdx
  =sec2x dxtanxsecx dx
  =tanxsecx+c

Option (b) is correct.

Mathematics

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