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Question

The integral value of k for which the equation (k12)x2+2(k12)x+2=0 possesses no real solutions is :

A
12
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B
13
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C
14
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D
15
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Solution

The correct option is B 13
We have
(k12)x2+2(k12)x+2=0
For no real solution, D < 0 i.e b24ac<0
[2(k12)]24(k12)×2<0
2(k12)[2(k12)4]<0
(k12)[2k244]<0
(k12)(2k28)<0
12<k<14
k=13

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