The integral value of $x$ satisfying $6 x^{2} - 7 x + 2 = 0$

- 2

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Solution

The correct option is D none
Given equation is: $6 x^{2} - 7 x + 2 = 0$
$6 x^{2} - 4 x - 3 x + 2 = 0$
$2 x (3 x - 2) - (3 x - 2) = 0$
$(2 x - 1) (3 x - 2) = 0$
Then $3 x = 1$ or $3 x = 2$
$x = \frac{1}{3}$ or $x = \frac{2}{3}$

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