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Absolute Value Function

The integral ...

Question

The integral values of $^{'} a^{'}$ for which the equation ${cos}^{2} x - (a^{2} + a + 5) | cos x | + (a^{3} + 3 a^{2} + 2 a + 6) = 0$ has real solution(s).

- 3

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- 2

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- 1

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Solution

The correct options are
A $- 3$
B $- 2$

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Similar questions

^{'} a^{'}

{cos}^{2} x - (a^{2} + a + 5) | cos x | + (a^{3} + 3 a^{2} + 2 a + 6) = 0

a

a sin x + cos 2 x = 2 a - 7

a_{0}, a_{1}, a_{2}, a_{3}

a_{0} + \frac{a_{1}}{2} + \frac{a_{2}}{3} + \frac{a_{3}}{4} = 0

a_{0} + a_{1} x + a_{2} x^{2} + a_{3} x^{3} = 0

a

a sin x + cos 2 x = 2 a - 7

^{'} a^{'}

4 {c o s e c}^{2} (π (a + x)) + a^{2} - 4 a = 0

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