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Question

The integraldx equals (for some arbitrary constant k)


A
1(secx+tanx)112{11117(secx+tanx)2}+k
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B
1(secx+tanx)112{11117(secx+tanx)2}+k
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C
1(secx+tanx)112{111+17(secx+tanx)2}+k
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D
1(secx+tanx)112{111+17(secx+tanx)2}+k
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Solution

The correct option is C 1(secx+tanx)112{111+17(secx+tanx)2}+k

Put sec x + tan x = t

(sec x tan x + sec2x) dx = dt

sec x. t dx = dt


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