The integrated rate equation is $R t = l o g C_{0} - l o g C_{t}$ . The straight line graph is obtained by plotting:

time vs l o g C_{t}

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\frac{1}{t i m e} vs C_{t}

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time vs C_{t}

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\frac{1}{t i m e} vs \frac{1}{C_{t}}

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Solution

The correct option is C $time vs l o g C_{t}$
$R t = l o g C_{o} - l o g C_{t}$
$R$ is the rate constant.
Let $l o g C_{t} = y$ and $t = x$
$R_{x} = l o g C_{o} - y$
$y = l o g C_{o} - R x$
$∴ t i m e v s l o g C_{t}$ gives straight line.

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