The Integrating Factor (IF) of the differential equation xdydx−y=2x2 is
(a)e−x
(b)e−y
(c)1x
(d)x
Given, differential equation is xdydx−y=2x2⇒dydx+(−1x)y=2x
It is a linear differential equation of the form dydx+Py=Q
∴P=−1x and Q=2x and IF=e∫Pdx⇒IF=e∫(−1x)dx⇒IF=e−log|x|⇒IF=elog|x|−1=1x
An integrating factor for the given equation is 1x(assuming x>0).
Hence, the correct option is (c).