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Question

The integrating factor of differential equation cosxdy=y(sinxy)dx is

A
tanx
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B
secx
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C
etanx
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D
esecx
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Solution

The correct option is A secx
dydx=ytanxy2secx
dydxytanx=y2secx
1y2dydx1ytanx=secx (*)
Substitute 1y=t
1y2dydx=dtdx By (*) we have
dtdx+ttanx=secx, which is linear in t
I.F. =etanxdx=elog(secx)=secx

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