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Question

The integrating factor of the differential equation cosx(dydx)+ysinx=1 is

A
secx
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B
tanx
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C
sinx
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D
cotx
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Solution

The correct option is A secx
The given differential equation is
cosx{dydx}+ysinx=1
dydx+ysinxcosx=1cosx
IF=esinxcosxdx=elogsecx=secx

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