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Question

The integrating factor of the differential equation xdydx-y=2x2
(a) e−x

(b) ey

(c) 1x

(d) x

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Solution

c 1x


We have,

xdydx-y=2x2dydx-1xy=2xComparing with dydx+Py=Q, we getP=-1x Q=2xNow,I.F.=e-1xdy =e-logx=elog1x=1x

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