The integration factor of differential equation (1+x2)dydx+2xy=4x2 is
log(1 + x2)
(1 + x2)
tan-1x
2 tan-1x
Here p=2x1+x2I.F=e∫pdx=elog(1+x2)=1=x2
Find the equation of a curve passing through origin and satisfying the differential equation (1+x2)dydx+2xy=4x2