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Question

The integration factor of differential equation (1+x2)dydx+2xy=4x2 is


A

log(1 + x2)

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B

(1 + x2)

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C

tan-1x

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D

2 tan-1x

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Solution

The correct option is B

(1 + x2)


Here p=2x1+x2I.F=epdx=elog(1+x2)=1=x2


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