The intensity of central fringes in the interference pattern produced by two identical slits is I. When one of the slits is closed then the intensity at the same point is Io. The relation between the I and Io is
A
I=4Io
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B
I=2Io
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C
I=Io
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D
I=Io2
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Solution
The correct option is CI=4Io when one of the slit is closed the intensity is only due to the remaining one hence the resultant intensity is same as the intensity of source Io when the two slits are oprn then the intensity is I=(√Io+√Io)2=4Io option A is correct