Question

The intensity of light emerging from one of the slits in a Young's double slit experiment is found to be 1.5 times the intensity of light emerging from the other slit. What will be the approximate ratio of intensity of an interference maximum to that of an interference minimum?

• A. 2.25
• B. 98
• C. 5
• D. 9.9

Answer 1

The correct option is B 98

$I_2=1.5I_1\frac{I_{max}}{I_{min}}={\left[\frac{\sqrt{I_1}+\sqrt{I_2}}{\sqrt{I_1}-\sqrt{I_2}}\right]}^2={\left[\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}}\right]}^2\approx 98$