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Question

The intensity of sound from a point source is 1.0 × 106m2 at a distance of 5.0 m from the source. What will be the intensity at a distance of 25 m from the source?



Solution

The correct option is A


The power of the sound wave is intensity × surface area

power =1 × 108 × 4π × 25

=100π 108 = 106π W

Intensity at 25m =powersurfacearea

=106π4π(25)2

=106625 × 4

=1062500

=0.04 × 108 Wm2

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