The intensity of sound wave gets reduced by 20% on passing through a slab. The reduction in intensity onpassing through two consecutive slabs is
A
40%
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B
36%
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C
30%
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D
50%
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Solution
The correct option is B 36% Let initial intensity is I. On first passes the intensity loss will be 20% of I. So I1=0.8I. On second passage the loss will be 20% of 0.8 I. 20100×810I=0.16I So the final intensity will be 0.8I−0.16I=0.64I. So loss will be 0.64I−II×100 36%