Question

The interatomic distance for a metal is $3\times {10}^{-10}m$ If the interatomic force constant is $3.6\times {10}^{-9}N/A$ then the young's modulus in $N/m^2$ will be

• A. $1.2\times {10}^{11}$
• B. $4.2\times {10}^{11}$
• C. $10.8\times {10}^{-19}$
• D. $2.4\times {10}^{10}$

Answer 1

The correct option is A $1.2\times {10}^{11}$

The young's modulus is given by $Y=\frac{F/A}{\delta l/l}$

So,

$Y=\frac{3.6\times {10}^{-9}N/A^{\circ }}{3\times {10}^{-10}m}=1.2\times {10}^{11}N/m^2$