The intercept cut off from y-axis is twice that from x-axis by the line and line is passes through (1, 2) then its equation is

2x + y = 4

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2x + y +4 = 0

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2x – y = 4

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2x – y + 4 = 0

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Solution

The correct option is A 2x + y = 4
Let the intercept be a and 2a, then the equation of line is $\frac{x}{a} + \frac{y}{2 a} = 1$ , but it also passes through (1,2)
therefore a = 2.
Hence the required equation is 2x + y = 4.

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Similar questions

Q. The intercept cut-off by a line from y-axis is twice than from x-axis and the line passes through the point (1, 2). The equation of the line is
(a) 2x + y = 4
(b) 2x + y + 4 = 0
(c) 2x – y = 4
(d) 2x – y + 4 = 0

Q. The intercept made by a line on y-axis is double to the intercept made by it on x-axis. If it passes through

(1, 2)

then its equation.

Q. Find the equation of line which passes through a point

(0, 1)

and intercept cut by line at x axis is three times the intercept cut at y-axis.

If a line passes through the point (1, 2) and cuts off positive intercepts on the x–axis and y–axis in the ratio 2 : 3, find the equation of the line.

Find the equation of the straight line which cuts off intercepts on x-axis twice that on y-axis and is at a unit distance from the origin.

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The intercept cut off from y-axis is twice that from x-axis by the line and line is passes through (1, 2) then its equation is

The correct option is A 2x + y = 4Let the intercept be a and 2a, then the equation of line is xa+y2a=1, but it also passes through (1,2) therefore a = 2. Hence the required equation is 2x + y = 4.

The correct option is A 2x + y = 4
Let the intercept be a and 2a, then the equation of line is $\frac{x}{a} + \frac{y}{2 a} = 1$ , but it also passes through (1,2)
therefore a = 2.
Hence the required equation is 2x + y = 4.