The intercept form of the line 3 x -4 y -12-0 isA- x-4-y-3-1B- x-4-y-3-2C- x-4-y-3-2D- x-4-y-3-1

The correct option is A x 4+y3=13x 4y+12=0 ⇒ 3x 4y= 12 ⇒x 4+y3=1 ...

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Standard XII

Mathematics

Perpendicular Form of a Straight Line

The intercept...

Question

The intercept form of the line $3 x - 4 y + 12 = 0$ is

\frac{x}{4} - \frac{y}{3} = 1

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\frac{x}{- 4} + \frac{y}{3} = 1

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\frac{x}{- 4} + \frac{y}{3} = 2

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\frac{x}{4} - \frac{y}{3} = 2

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Solution

The correct option is B $\frac{x}{- 4} + \frac{y}{3} = 1$
$3 x - 4 y + 12 = 0$
$\Rightarrow 3 x - 4 y = - 12$
$\Rightarrow \frac{x}{- 4} + \frac{y}{3} = 1$

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Similar questions

Q. The equation of the straight line passing through the intersection of the lines

x - y - 1 = 0

and

2 x - 3 y + 1 = 0

and parallel to

3 x + 4 y - 14 = 0

Q. The equation of the straight line passing through the point of intersection of

x + 2 y = 5

and

3 x + 7 y = 17

and perpendicular to the straight line

3 x + 4 y = 10

The equation of a line is 3 – 4y + 12 = 0.

Find the slope of the line and equation of ⊥ to the given line, which passes through the point of intersection of the lines – y + 2 = 0 & 3 + y – 10 = 0

Q. The equation of the straight line which passes through the intersection of the lines

x + 2 y = 5

and

3 x + 7 y = 17

and is perpendicular to the line

3 x + 4 y = 14

Q. The equation of the line parallel to the line

3 x - 4 y + 2 = 0

and passing through

(- 2, 3)

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The intercept form of the line 3x−4y+12=0 is

The correct option is B x−4+y3=13x−4y+12=0 ⇒3x−4y=−12 ⇒x−4+y3=1

The intercept form of the line $3 x - 4 y + 12 = 0$ is

The correct option is B $\frac{x}{- 4} + \frac{y}{3} = 1$
$3 x - 4 y + 12 = 0$
$\Rightarrow 3 x - 4 y = - 12$
$\Rightarrow \frac{x}{- 4} + \frac{y}{3} = 1$