Equation of Tangent at a Point (x,y) in Terms of f'(x)
The intercept...
Question
The intercepts on x-axis made by tangents to the curve, y=∫x0|t| dt, x∈R, which are parallel to the line y=2x, are equal to
A
±2
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B
±3
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C
±4
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D
±1
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Solution
The correct option is D±1 dydx=|x|=2⇒x=±2⇒y=∫20|t| dt =2 for x=2 and y=∫−20|t| dt =−2 for x=−2 Hence the equations of the tangents are y−2=2(x−2)⇒y=2x−2 and y+2=2(x+2)⇒y=2x+2 Putting y=0, we get x=1 and −1.