The interior angles of a regular polygon measure $120^{o}$ each. The number of diagonal of the polygon is

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Solution

The correct option is D 9
Given interior angles of a regular polygon $= 120^{o}$ each.
$\Rightarrow (\frac{2 n - 4}{n}) \times 90^{0} = 120^{0}$
$\Rightarrow n = 6$
$∴$ No. of diagonals $= \frac{n . (n - 3)}{2} = 9$

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The interior angles of a regular polygon measure 120o each. The number of diagonal of the polygon is

The correct option is D 9Given interior angles of a regular polygon =120o each.⇒(2n−4n)×900=1200⇒n=6∴ No. of diagonals =n.(n−3)2=9

The interior angles of a regular polygon measure $120^{o}$ each. The number of diagonal of the polygon is

The correct option is D 9
Given interior angles of a regular polygon $= 120^{o}$ each.
$\Rightarrow (\frac{2 n - 4}{n}) \times 90^{0} = 120^{0}$
$\Rightarrow n = 6$
$∴$ No. of diagonals $= \frac{n . (n - 3)}{2} = 9$