The internal and external diameters of a hollow cylinder are measured with the help of a Vernier callipers. Their values are $4.23 \pm 0.01$ cm and $3.87 \pm 0.01 c m$ , respectively. The thickness of the wall of the cylinder is

0.36 \pm 0.02 c m

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0.18 \pm 0.02 c m

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0.36 \pm 0.01 c m

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0.18 \pm 0.01 c m

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Solution

The correct option is B $0.18 \pm 0.02 c m$
Thickness $= 4.23 - 3.87 = 0.18$
Error $= 0.01 + 0.01 = 0.02$
As error always gets added
So,
Thickness $= 0.18 \pm 0.02$ cm.

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The internal and external diameters of a hollow cylinder are measured with the help of a Vernier callipers. Their values are 4.23±0.01cm and 3.87±0.01cm, respectively. The thickness of the wall of the cylinder is

The correct option is B 0.18±0.02cmThickness =4.23−3.87=0.18Error =0.01+0.01=0.02As error always gets addedSo,Thickness =0.18±0.02 cm.

The internal and external diameters of a hollow cylinder are measured with the help of a Vernier callipers. Their values are $4.23 \pm 0.01$ cm and $3.87 \pm 0.01 c m$ , respectively. The thickness of the wall of the cylinder is

The correct option is B $0.18 \pm 0.02 c m$
Thickness $= 4.23 - 3.87 = 0.18$
Error $= 0.01 + 0.01 = 0.02$
As error always gets added
So,
Thickness $= 0.18 \pm 0.02$ cm.