the internal and external radii of a hollo sphere are 3cm and 5cm. the sphere is melted to form a solid cylinder of height 22/3 cm find the diameter and curved surface area of the cylinder

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Solution

here R=5cm
r=3cm

h=22/3cm

Let radius of cylinder be x
therefore 4/3 * pie * (R^3-r^3) = piex^222/3
thus 5^3-3^3 = 2x^2

17.818 = x^2

x=4.221

Diameter=2x=8.44cm

C.S.A = 2pier*h=194.48cm^2

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the internal and external radii of a hollo sphere are 3cm and 5cm. the sphere is melted to form a solid cylinder of height 22/3 cm find the diameter and curved surface area of the cylinder

here R=5cm r=3cm h=22/3cm Let radius of cylinder be x therefore 4/3 * pie * (R^3-r^3) = pie*x^2*22/3 thus 5^3-3^3 = 2x^2 17.818 = x^2 x=4.221 Diameter=2x=8.44cm C.S.A = 2*pie*r*h=194.48cm^2

here R=5cm
r=3cm

h=22/3cm

Let radius of cylinder be x
therefore 4/3 * pie * (R^3-r^3) = piex^222/3
thus 5^3-3^3 = 2x^2

17.818 = x^2

x=4.221

Diameter=2x=8.44cm

C.S.A = 2pier*h=194.48cm^2