Question

The internal energy and the work done by a system decreases by same amount then

• A. The temperature must decrease
• B. The process must be adiabatic
• C. The temperature must decrease and The process must be adiabatic are both
• D. The process must be isothermal

Answer 1

The correct option is C

The temperature must decrease and The process must be adiabatic are both

Loss in internal energy = work done by the system, dQ = 0, therefore process is adiabatic. Loss in internal energy shows there would be a decrease in temperature.