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Standard XII
Physics
1st Law of Thermodynamics
The internal ...
Question
The internal energy change in a system that has absorbed
2
K
c
a
l
of heat and done
500
J
of work is
A
8900
J
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B
6400
J
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C
5400
J
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D
7900
J
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Solution
The correct option is
A
7900
J
Given:
Heat absorbed = 2 Kcal
work done = 500 J
Solution:
As we know, according to the law of thermodynamics
△
U
=
Q
−
W
(1)
where, U is the change in the internal energy,
Q denotes the heat given to the system and
W denotes the work done by the system.
Also,
1
c
a
l
=
4.2
J
So,
2
K
c
a
l
=
2
×
1000
×
4.2
Substituting the values in equation (1) we get,
△
U
=
2
×
1000
×
4.2
−
500
△
U
=
7900
J
Hence, the correct option is (D).
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