The internal energy of a gas is given by $U = 2 P V$ . it expands from $V_{o} t o 2 V_{o}$ against a constant pressure $P_{o} .$ The heat absorbed by the gas in the process is

2 P_{o} V_{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 P_{o} V_{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 P_{o} V_{o}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

P_{o} V_{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $3 P_{o} V_{o}$
Work done is given by:
$w = \int P d V = P (V_{2} - V_{1}) = P_{o} (2 V_{o} - V_{o}) = P_{o} V_{o}$
Internal energy $U = 2 P V$
$Δ U = 2 P_{o} (2 V_{o} - V_{o}) = 2 P_{o} V_{o}$
First law of thermodynamics gives us the relation:
$q = Δ U + w$
$q = 2 P_{o} V_{o} + P_{o} V_{o} = 3 P_{o} V_{o}$
Option C is correct.

Suggest Corrections

Similar questions

Q. The internal energy of a gas is given by

U = (2 P V + 20) J

. It expands from

100 {cm}^{3}

200 {cm}^{3}

against a constant pressure of

200 kPa

. Calculate the heat absorbed by the gas in the process.

Q. The internal energy of a gas is given by

U = (2 P V + 20) J

. It expands from

100 {cm}^{3}

200 {cm}^{3}

against a constant pressure of

200 kPa

. Calculate the heat absorbed by the gas in the process.

The internal energy of a gas is given by $U = 1.5 pv$ . It expands from 100 $c m^{3}$ to 200 $c m^{3}$ against a constant pressure of $1.0 \times 10^{5} Pa$ . Calculate the heat absorbed by the gas in the process.

Q. If a gas absorbs

200 J

of heat and expands by

500 c m^{3}

against a constant pressure of

2 \times 10^{5} N m^{- 2}

, then the change in internal energy is:

A gas expands from 1.5 to 6.5 L against a constant pressure of 0.5 atm and during this process the gas also absorbs 100 J of heat. The change in the internal energy of the gas is:

Join BYJU'S Learning Program

The internal energy of a gas is given by U=2PV. it expands from Voto2Vo against a constant pressure Po. The heat absorbed by the gas in the process is

The correct option is C 3PoVoWork done is given by:w=∫PdV=P(V2−V1)=Po(2Vo−Vo)=PoVoInternal energy U=2PVΔU=2Po(2Vo−Vo)=2PoVoFirst law of thermodynamics gives us the relation:q=ΔU+wq=2PoVo+PoVo=3PoVoOption C is correct.

The internal energy of a gas is given by $U = 2 P V$ . it expands from $V_{o} t o 2 V_{o}$ against a constant pressure $P_{o} .$ The heat absorbed by the gas in the process is