The internal energy of helium gas is 250 joule per litre, then the pressure of gas will be

10^{5} N / m^{2}

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1.7 \times 10^{5} N / m^{2}

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1.3 \times 10^{5} N / m^{2}

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2.4 \times 10^{5} N / m^{2}

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Solution

The correct option is B $1.7 \times 10^{5} N / m^{2}$
$U = \frac{3 n R T}{2} = \frac{3}{2} P V$
$P = \frac{2 U}{3 V} = \frac{2}{3} . (\frac{250}{10^{- 3}}) \frac{j o u l e}{m^{3}}$
$= \frac{500}{3} \times 10^{3} = \frac{5}{3} \times 10^{5} J / m^{3}$
$= 1.7 \times 10^{5} N / m^{2}$

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The internal energy of helium gas is 250 joule per litre, then the pressure of gas will be

The correct option is B 1.7×105 N/m2U=3nRT2=32PV P=2U3V=23.(25010−3)joulem3 =5003×103=53×105J/m3 =1.7×105 N/m2

The correct option is B $1.7 \times 10^{5} N / m^{2}$
$U = \frac{3 n R T}{2} = \frac{3}{2} P V$
$P = \frac{2 U}{3 V} = \frac{2}{3} . (\frac{250}{10^{- 3}}) \frac{j o u l e}{m^{3}}$
$= \frac{500}{3} \times 10^{3} = \frac{5}{3} \times 10^{5} J / m^{3}$
$= 1.7 \times 10^{5} N / m^{2}$