The internal length, breadth, height of a box are $30 c m, 24 c m, 15 c m$ . Find the largest number of cubes which can be placed inside the box; if the edge of each cube is $5 c m$ .

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Solution

Cubes along length $= 30 / 5 = 6$
Cubes along width $= 24 / 5 = 4.5, t a k e$ 4$$
cube along height $= 15 / 5 = 3$
$∴$ The total no. of cubes placed $= 6 \times 4 \times 3 = 72$

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The internal length, breadth, height of a box are 30 cm,24 cm,15 cm. Find the largest number of cubes which can be placed inside the box; if the edge of each cube is 5 cm.

Cubes along length =30/5=6Cubes along width =24/5=4.5,take4$$cube along height =15/5=3∴ The total no. of cubes placed =6×4×3=72

The internal length, breadth, height of a box are $30 c m, 24 c m, 15 c m$ . Find the largest number of cubes which can be placed inside the box; if the edge of each cube is $5 c m$ .

Cubes along length $= 30 / 5 = 6$
Cubes along width $= 24 / 5 = 4.5, t a k e$ 4$$
cube along height $= 15 / 5 = 3$
$∴$ The total no. of cubes placed $= 6 \times 4 \times 3 = 72$