The internal measures of a cuboidal room are $12 m \times 8 m \times 4 m$ . Find the total cost of whitewashing off four walls of a room, if the cost of whitewashing is Rs. $5$ per $m^{2}$ . What will be the cost of whitewashing if the ceiling of the room is also whitewashed?

1288

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1380

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1280

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1880

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Solution

The correct option is C Rs $1280$
Area to be white washed $= 2 (12 \times 4) + 2 (8 \times 4) + (12 \times 8)$
$= 2 (48) + 2 (32) + 96$
$= 96 + 64 + 96$
$= 256 m^{2}$
Total cost $=$ cost per $m^{2} \times$ total area
$= 5 \times 256$
$= R s .1280$

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The internal measures of a cuboidal room are 12m×8m×4m. Find the total cost of whitewashing off four walls of a room, if the cost of whitewashing is Rs. 5 per m2. What will be the cost of whitewashing if the ceiling of the room is also whitewashed?

The correct option is C Rs 1280Area to be white washed =2(12×4)+2(8×4)+(12×8) =2(48)+2(32)+96 =96+64+96 =256m2Total cost = cost per m2× total area =5×256 =Rs.1280

The internal measures of a cuboidal room are $12 m \times 8 m \times 4 m$ . Find the total cost of whitewashing off four walls of a room, if the cost of whitewashing is Rs. $5$ per $m^{2}$ . What will be the cost of whitewashing if the ceiling of the room is also whitewashed?

The correct option is C Rs $1280$
Area to be white washed $= 2 (12 \times 4) + 2 (8 \times 4) + (12 \times 8)$
$= 2 (48) + 2 (32) + 96$
$= 96 + 64 + 96$
$= 256 m^{2}$
Total cost $=$ cost per $m^{2} \times$ total area
$= 5 \times 256$
$= R s .1280$