The internal resistance of a $2.1 V$ cell, which gives a current of $0.2 A$ through a resistance of $10 Ω$ , is -

1.0 Ω

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0.2 Ω

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0.5 Ω

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0.8 Ω

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Solution

The correct option is C $0.5 Ω$

$I = \frac{E}{r + R}$

$0.2 = \frac{2.1}{r + 10}$

$0.2 \times (r + 10) = 2.1$

$r = 0.5 Ω$

 Hence, $(C)$ is the correct answer.

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The internal resistance of a 2.1 V cell, which gives a current of 0.2 A through a resistance of 10 Ω, is -

The correct option is C 0.5 Ω I=Er+R 0.2=2.1r+10 0.2×(r+10)=2.1 r=0.5 Ω  Hence, (C) is the correct answer.

The internal resistance of a $2.1 V$ cell, which gives a current of $0.2 A$ through a resistance of $10 Ω$ , is -

The correct option is C $0.5 Ω$

$I = \frac{E}{r + R}$

$0.2 = \frac{2.1}{r + 10}$

$0.2 \times (r + 10) = 2.1$

$r = 0.5 Ω$

 Hence, $(C)$ is the correct answer.