The internal resistance of an ammeter is 0.2 Ω. Its full scale deflection current is 10A. The P.d across the terminals when a current of 5A is flowing through it is
Given : Internal resistance of ammeter =0.2Ω
To find : Potential difference (V) when Current (I) =5A
The ammeter follows the ohm’s law.
So, V=IR holds true.
V= (5A)×(0.2Ω) =1V