The given function y is defined as,
y= x 2 ⋅ e −x
The derivative of the function y is given as,
y ′ = dy dx = d( x 2 ⋅ e −x ) dx =2x e −x − x 2 e −x =x e −x ( 2−x )
We have to find disjoint points in the real axis, so
dy dx =0 x e −x ( 2−x )=0
The solutions to the above equation are,
x=0 x=2
Hence, points x=0 and 2 divide the real axis into three intervals ( −∞,0 ), ( 0,2 ) and ( 2,∞ ).
For the intervals ( −∞,0 ) and ( 2,∞ ), y ′ is less than 0 as e −x is always positive.
Therefore, y is decreasing in intervals ( −∞,0 ) and ( 2,∞ ).
For the interval ( 0,2 ),
y ′ >0
As y ′ >0; therefore, y is strictly increasing in the interval ( 0,2 ).
Hence, the correct option is D.