The interval in which the function f(x)=x3−6x2+9x+10 is increasing in
A
[1,3]
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B
(−∞,1)∪(3,∞)
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C
(−∞,−1]∪[3,∞)
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D
(−∞,1]∪[3,∞)
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Solution
The correct option is D(−∞,1]∪[3,∞) f(x)=x3−6x2+9x+10 ⇒f′(x)=3x2−12x+9=3(x−1)(x−3) f′(x)≥0 in the interval (−∞,1]∪[3,∞). ∴f is increasing in (−∞,1]∪[3,∞)