The inverse of y=5logx is
x=5log(y)
x=5log(y)c
x=y1log(5)
x=51log(y)
Explanation for the correct option:
Simplify the equation in terms of y
y=5logx
Taking log both sides
log(y)=log5log(x)
Let the base of log be 5
log5(y)=loge(x) [∵logaa=1]
Taking anti-log
elog5(y)=x⇒ylog5(e)=x⇒y1log5=x ∵bloge(a)=aloge(b)
Hence, option C is correct.