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Activation Energy

The inversion...

Question

The inversion of cane sugar to produce glucose and fructose is represented by the reaction
$C_{12} H_{22} O_{11} + H_{2} O H^{+} - - \to C_{6} H_{12} O_{6} + C_{6} H_{12} O_{6}$
The reaction is:

second order

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unimolecular

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pseudo uni-molecular

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bi molecular

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Solution

The correct option is D pseudo uni-molecular
Inversion of Cane Sugar to produce glucose and fructose is a Pseudo uni-molecular Reaction.
Here the rate of reaction is made first order by changing the concentration of sucrose ( $C_{12} H_{22} O_{11}$ ).

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Similar questions

C_{12} H_{22} O_{11} + H_{2} O \to C_{6} H_{12} O_{6} + C_{6} H_{12} O_{6}

2.12 \times 10^{- 4} L {m o l}^{- 1} {s e c}^{- 1}

27^{o} C

1.07 \times 10^{5} J {m o l}^{- 1}

37^{o} C

C_{12} H_{22} O_{11} + H_{2} O I n v e r t a s e - ----- \to C_{6} H_{12} O_{6} A + C_{6} H_{12} O_{6} B

C_{6} H_{12} O_{6} z y m a s e - --- \to 2 C_{2} H_{5} O H + 2 {C O}_{2}

A

B

α

C_{12} H_{22} O_{11} (a q) + H_{2} O (l) ⟶ 2 C_{6} H_{12} O_{6} (a q)

Δ_{f} H^{o} (H_{2} O, l) = - 285.85 k J

{m o l}^{- 1}

Δ_{f} H^{o} (C_{6} H_{12} O_{6}, a q) = - 1263.1 k J

{m o l}^{- 1}

Δ_{f} H^{o} (C_{12} H_{22} O_{11}, a q) = - 2238.3.1 k J

{m o l}^{- 1}

540 g

(C_{6} H_{12} O_{6})

1.80 g

(C_{6} H_{12} O_{6})

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