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Idea of Hybridisation

The ion with ...

Question

The ion with largest number of lone pairs on the halogen:

C l O^{-}

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C l O_{2}^{-}

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C l O_{3}^{-}

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C l O_{4}^{-}

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Solution

The correct option is D $C l O^{-}$
Chlorine atom in each of these molecules is $s p^{3}$ hybridized.
$C l O^{-}$ has three lone pairs and $1$ bond pair.
$C l O_{2}^{-}$ has two lone pairs and $2$ bond pair.
$C l O_{3}^{-}$ has one lone pairs and $3$ bond pair.
$C l O_{4}^{-}$ has no lone pairs and $4$ bond pair.

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Similar questions

C l O^{-},

C l O_{2}^{-}, C l O_{3}^{-}, C l O_{4}^{-}

3 C l O^{-} ⟶ C l O_{2}^{-} + 2 {C l}^{-}

C l O^{-} + C l O^{-} K_{1} - \to C l O_{2}^{-} + {C l}^{-}

C l O_{2}^{-} + C l O^{-} K_{2} - \to C l O_{3}^{-} + {C l}^{-}

3 C l O^{-} \to C l O_{3}^{-} + 2 C l

C l O^{-} + C l O^{-} K_{1} - \to C l O_{2}^{-} + C l^{-}

C l O_{2}^{+} C l O^{-} k_{2} - \to C l O_{3}^{-} + C l^{-}

3 C l O^{-} \to C l O_{3}^{-} + 2 C l^{-}

C l O^{-} + C l O^{-} \to C l O_{2}^{-} + C l^{-} - - - - (s l o w)

C l O_{2}^{-} + C l O^{-} \to C l O_{3}^{-} + C l^{-} - - - - - (f a s t)

N a O H

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