The ion with pyramidal shape is:

S_{2} O_{3}^{2 -}

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S O_{3}^{- 2}

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S O_{4}^{2 -}

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S_{2} O_{8}^{2 -}

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Solution

The correct option is C $S O_{3}^{- 2}$
$S O_{3}^{2 -} = 3 + \frac{6 - 6 + 2}{2}$
$=$ 3 (Bond pair) + 1 (Lone pair)
$S p^{3}$ hybridisation, Pyramidal shape.

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