Question

The ionastion energy of the electron in the hydrogen atom in its ground state is $13.6eV$. The atoms are excited to higher energy levels to emit radiations of $6$ wavelengths. Maximum wavelength of emitted radiation corresponds to the transition between :

• A. $n=3$ to $n=1$ states
• B. $n=4$ to $n=3$ states
• C. $n=3$ to $n=2$ states
• D. $n=2$ to $n=1$ states

Answer 1

The correct option is B $n=4$ to $n=3$ states

Number of wavelengths $=\frac{n(n-1)}{2}$
where, n = number of orbit from which transition takes place.
$\therefore 6=\frac{n(n-1)}{2}$
$n=4$
$\therefore$ The wavelength of emitted radiations will be maximum for transition $n=4$ to $n=3.$