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Byju's Answer
Standard XII
Chemistry
Types of Redox Reactions
The ionic equ...
Question
The ionic equivalent conductivities of
C
2
O
2
−
4
,
K
+
,
and
N
a
+
ions are x, y and z S
c
m
2
E
q
−
1
respectively. Calculate
A
0
e
q
of
(
N
a
O
O
C
−
C
O
O
K
)
.
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Solution
A
0
e
q
(
N
a
O
O
C
-
C
O
O
K
)
=
A
0
e
q
(
N
a
+
)
+
A
0
e
q
(
K
+
)
+
A
0
e
q
(
C
2
O
2
−
4
)
=
(
z
+
y
+
x
)
=
(
x
+
y
+
z
)
S
c
m
2
e
q
−
1
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0
Similar questions
Q.
The ionic equivalent conductivities of
K
+
, Al^{3+}, and
S
O
2
−
4
ions are x,y and z
S
c
m
2
e
q
−
1
, respectively. Calculate
Λ
0
m
and
Λ
0
e
q
for
(
K
2
S
O
4
.
A
l
2
(
S
O
4
)
3
.
24
H
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O
)
(Potash alum).
Q.
If the ionic equivalent conductivities of
K
+
A
l
3
+
,
and
S
O
2
−
4
ions are 4, 4, and 1
S
c
m
2
E
q
−
1
, respectively. Calculate the value of
∧
0
e
q
for Potash alum
(
K
2
S
O
4
.
A
l
2
(
S
O
4
)
3
.
24
H
2
O
)
Q.
Given the ionic conductance of
C
O
O
⊝
|
C
O
O
⊝
,
K
⊕
, and
N
a
⊕
are 74,50 and
73
c
m
2
o
h
m
−
1
e
q
−
1
, respectively. The equivalent conductance at infinite dilution of the salt
C
O
O
N
a
|
C
O
O
K
is :
Q.
At 291 K, the equivalent conductivities at infinite dilution of
N
H
4
C
l
,
N
a
O
H
and
N
a
C
l
are
129.8
,
217.5
and
108.9
S
c
m
2
e
q
−
1
respectively. The equivalent conductivity at infinite dilution of
N
H
4
O
H
is:
Q.
Molar conductivities of oxalate,
K
+
and
N
a
+
ions at infinite dilution are
148.2
,
50.1
,
73.5
S
c
m
2
m
o
l
−
1
respectively. Then, e
quivalent conductivity at infinite dilution for sodium-potassium oxalate
[
(
C
O
O
−
)
2
N
a
+
K
+
]
will be:
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