Question

The ionic product of water is ${10}^{-14}$. What is the $H^{+}$ ion concentration of a $0.01M$ $NaOH$ solution?

• A. ${10}^{-14}M$
• B. $14M$
• C. $13M$
• D. ${10}^{-12}M$

Answer 1

The correct option is D ${10}^{-12}M$

$NaOH$ is a strong electrolyte and completely dissociates in solution.
Hence, $\left[O{H}^{-}\right]=0.01$.
The ionic product of water is ${10}^{-14}$
Hence, $k_w=\left[H^{+}\right]\left[O{H}^{-}\right]={10}^{-14}$
or $\left[H^{+}\right]=\frac{{10}^{-14}}{\left[O{H}^{-}\right]}=\frac{{10}^{-14}}{0.01}={10}^{-12}$