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Question

# The ionic product of water is found to be 1×10−12 mole2/l2 at 60oC. What would be the nature of solution with pH=7?

A
Basic
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B
Acidic
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C
Neutral
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D
Cannot be determined
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Solution

## The correct option is C BasicIn pure water at 60oC temperature the Kw value:[H+][OH−]=1.00×10−12But in pure water, the [H+]=[OH−]. can replace the [OH−] term in the Kw expression by another [H+].[H+]2=1.00×10−12Taking the square root of each side gives:[H+]=1.00×10−6Converting that into pH:pH=−log10[H+]pH=6 At pH=6 solution will be neutral.At pH>6 solution is basic and pH<6 solution is acidic.

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