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Standard XII

Chemistry

Coordination Number

The ionic rad...

Question

The ionic radii of $A^{+}$ and $B^{-}$ are $1.7 A^{\circ}$ and $1.8 A^{\circ}$ respectively. Find the coordination number of $A^{+}$ .

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Solution

Radius ratio = $\frac{r a d i u s o f c a t i o n}{r a d i u s o f a n i o n} = \frac{1.7}{1.8}$ = 0.94
Since the ratio lies between 0.732 to 1, we can say that we are talking about a cubic void i.e. the coordination number is 8.

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The ionic radii of A+ and B− are 1.7A∘ and 1.8A∘ respectively. Find the coordination number of A+.

Radius ratio = radius of cationradius of anion=1.71.8 = 0.94 Since the ratio lies between 0.732 to 1, we can say that we are talking about a cubic void i.e. the coordination number is 8.

The ionic radii of $A^{+}$ and $B^{-}$ are $1.7 A^{\circ}$ and $1.8 A^{\circ}$ respectively. Find the coordination number of $A^{+}$ .

Radius ratio = $\frac{r a d i u s o f c a t i o n}{r a d i u s o f a n i o n} = \frac{1.7}{1.8}$ = 0.94
Since the ratio lies between 0.732 to 1, we can say that we are talking about a cubic void i.e. the coordination number is 8.