The ionic radii of A -and B -ions are 0-98 - 10-10 m and 1-81 - 10-10 m- The coordination number of each ion in AB isA- 4B- 8C- 6D- 2

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Question

The ionic radii of $A^{+}$ and $B^{-}$ ions are $0.98 \times 10^{- 10} m$ and $1.81 \times 10^{- 10} m$ . The coordination number of each ion in AB is

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Solution

The correct option is D
6

$\frac{r_{(+)}}{r_{(-)}} = \frac{0.98 \times 10^{- 10}}{1.81 \times 10^{- 10}} = 0.54$
As this is in between 0.414 and 0.732, the ionic solid has octahedral geometry and the co-ordination number of each ion in AB is 6.

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The ionic radii of A+ and B− ions are 0.98×10–10m and 1.81×10–10m. The coordination number of each ion in AB is

The correct option is D 6 r(+)r(−)=0.98×10−101.81×10−10=0.54 As this is in between 0.414 and 0.732, the ionic solid has octahedral geometry and the co-ordination number of each ion in AB is 6.

The ionic radii of $A^{+}$ and $B^{-}$ ions are $0.98 \times 10^{- 10} m$ and $1.81 \times 10^{- 10} m$ . The coordination number of each ion in AB is

The correct option is D
6

$\frac{r_{(+)}}{r_{(-)}} = \frac{0.98 \times 10^{- 10}}{1.81 \times 10^{- 10}} = 0.54$
As this is in between 0.414 and 0.732, the ionic solid has octahedral geometry and the co-ordination number of each ion in AB is 6.