The ionic radii of Cs and Cl are 0.165 nm and 0.181 nm respectively. Their atomic weights are 133 amu and 35.5 amu respectively. Then,
A
the lattice parameter (a) is 0.4 nm
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B
the lattice parameter can not be determined from this data
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C
the density of CsCl is 4.37×103 kg m3
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D
CsCl has a fcc structure on the basis of the given information
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Solution
The correct options are A the lattice parameter (a) is 0.4 nm C the density of CsCl is 4.37×103 kg m3 For CsCl type structures, 2(r++r−)=a√3 So, a=2√3(0.165+0.181)=0.4 mm Density =Z×MNA×a3=1×(133+35.5)6.02×1023×(4×10−10)3=4.37×103 kg m3 (by converting units)