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Question

The ionic radius of Cr is minimum in which of the following compounds?

A
CrF3
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B
CrCl3
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C
Cr2O3
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D
K2CrO4
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Solution

The correct option is B K2CrO4
The oxidation state of Cr in different compounds are

CrCl3 ----- +3

CrF3 ------ +3

Cr2O3 ------ +3

K2CrO4 -------+6

As oxidation state of Cr is maximum (maximum positive charge) in K2CrO4 so ionic radii of Cr is minimum here.

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