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Question

The ionic strength of CH3COO ion in 0.1 M CH3COOH solution having Ka=1.8×105 is

A
0.1
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B
0.05
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C
6.7×104
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D
1.34×103
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Solution

The correct option is C 6.7×104
CH3COOHCH3COO+H+

[CH3COO]=Cα=CKaC=KaC=1.8×105×0.1=1.34×103

Ionic strength of CH3COO=12n [CH3COO]Z2=12×1×1.34×103×(1)2=6.7×104
where, n = no. of ions and Z= charge on the ion.
Option C is correct.

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